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adds(They can both access C<$count>, and since it has gone out of scope,there is no other way to access it.BEGIN {my $count = 1;sub increment_count { $count++ }sub return_count { $count }}To declare a file-private variable, you still use a lexical variable.A file is also a scope, so a lexical variable defined in the filecannot be seen from any other file.See L<perlsub/"Persistent Private Variables"> for more information.The discussion of closures in L<perlref> may help you even though wedid not use anonymous subroutines in this answer. SeeL<perlsub/"Persistent Private Variables"> for details.=head2 What's the difference between dynamic and lexical (static) X-Ref |
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